(3n^2-2)(4n+1)=0

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Solution for (3n^2-2)(4n+1)=0 equation: 


Simplifying
(3n2 + -2)(4n + 1) = 0

Reorder the terms:
(-2 + 3n2)(4n + 1) = 0

Reorder the terms:
(-2 + 3n2)(1 + 4n) = 0

Multiply (-2 + 3n2) * (1 + 4n)
(-2(1 + 4n) + 3n2 * (1 + 4n)) = 0
((1 * -2 + 4n * -2) + 3n2 * (1 + 4n)) = 0
((-2 + -8n) + 3n2 * (1 + 4n)) = 0
(-2 + -8n + (1 * 3n2 + 4n * 3n2)) = 0
(-2 + -8n + (3n2 + 12n3)) = 0
(-2 + -8n + 3n2 + 12n3) = 0

Solving
-2 + -8n + 3n2 + 12n3 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.

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